Chapter 1 - Unit 8
Iterative Constructs in Java
Class 10 - APC Understanding Computer Applications with BlueJ
Fill in the blanks
Question 1
When the statements are repeated sequentially a number of times in a program, the construct is known asloop.
Question 2
For loop is also known as entrycontrolled loop.
Question 3
do-while loop is called an exit controlled loop.
Question 4
do-while loop executes at least once, if the condition is false.
Question 5
while loop checks the condition first before its execution.
Question 6
To find the sum of any ten numbers, the loop will run ten times.
Answer the following questions
Question 1
What is 'for' loop? What are the parameters used in 'for' loop?
for loop is an entry-controlled loop. The following parameters are commonly used in a for loop:
- An initial value for the loop control variable.
- A condition—loop will iterate as long as this condition remains true.
- An update expression to modify the loop control variable after every iteration.
- Body of the loop which consists of the statements that needs to be repeatedly executed.
Below is an example of for loop, it prints the table of 2 till 12:
for (int i = 1; i <= 12; i++) {
int a = 2 * i;
System.out.println("2 x " + i + "\t= " + a);
}Question 2
Define the following with their constructs:
(a) Entry controlled loop
An entry-controlled loop checks the condition at the time of entry. Only if the condition is true, the program control enters the body of the loop. for and while loops are entry-controlled loops.
(b) Exit controlled loop
An exit-controlled loop checks the condition after executing its body. If the condition is true, loop will perform the next iteration otherwise program control will move out of the loop. do-while loop is an exit-controlled loop.
Question 3
Write down the syntax of:
(a) do - while
do {
//loop-body
} while (condition);
(b) while loop
while (condition) {
//loop-body
}
Question 4
What is the purpose of using
(a) break statement
break statement is used to unconditionally jump out of the loop
(b) continue statement in a program?
continue statement is used to unconditionally jump to the next iteration of the loop, skipping the remaining statements of the current iteration.
Question 5
Distinguish between while and do-while loop.
| while | do-while |
|---|---|
| It is an entry-controlled loop. | It is an exit-controlled loop. |
| It is helpful in situations where numbers of iterations are not known. | It is suitable when we need to display a menu to the user. |
Question 6
What is meant by an infinite loop? Give an example.
A loop which continues iterating indefinitely and never stops is termed as infinite loop. Below is an example of infinite loop:
for (;;)
System.out.println("Infinite Loop");Question 7
State one difference and one similarity between while loop and do-while loop.
Similarity — Both while and do-while are suitable in situations where numbers of iterations is not known.
Difference — while is an entry-controlled loop whereas do-while is an exit-controlled loop
Predict the output
Question 1
The following is a segment of a program.
x = 1; y = 1;
if(n>0)
{
x = x + 1;
y = y + 1;
}What will be the value of x and y, if n assumes a value:
(i) 1
Output
x = 2
y = 2
Explanation
As n is 1, so if condition is true. xand y are incremented by 1 so both become 2.
(ii) 0
Output
x = 1
y = 1
Explanation
As n is 1, so if condition is false. Values of both x and y remain unchanged.
Question 2
Analyze the following program segment and determine how many times the body of the loop will be executed (show the working).
x = 5; y = 50;
while(x<=y)
{
y = y / x;
System.out.println(y);
}Output
10
2
The loop will execute 2 times.
Explanation
| x | y | Remarks |
|---|---|---|
| 5 | 50 | Initial values |
| 5 | 10 | After 1st iteration |
| 5 | 2 | After 2nd iteration |
After 2 iterations y becomes less than x so condition of while loop becomes false and it stops executing.
Question 3
What will be the output of the following code?
int m=2;
int n=15;
for(int i=1;i<5;i++)
m++;
--n;
System.out.println("m="+m);
System.out.println("n="+n);Output
m=6
n=14
Explanation
As there are no curly braces after the for loop so only the statement m++; is inside the loop. Loop executes 4 times so m becomes 6. The next statement--n; is outside the loop so it is executed only once and n becomes 14.
Question 4
Analyze the following program segment and determine how many times the loop will be executed. What will be the output of the program segment?
int k=1,i=2;
while(++i<6)
k*=i;
System.out.println(k);Output
60
Explanation
This table shows the change in values of i and k as while loop iterates:
| i | k | Remarks |
|---|---|---|
| 2 | 1 | Initial values |
| 3 | 3 | 1st Iteration |
| 4 | 12 | 2nd Iteration |
| 5 | 60 | 3rd Iteration |
| 6 | 60 | Once i becomes 6, condition is false and loop stops iterating. |
Notice that System.out.println(k);is not inside while loop. As there are no curly braces so only the statement k *= i; is inside the loop. The statementSystem.out.println(k); is outside the while loop, it is executed once and prints value of k which is 60 to the console.
Question 5
Give the output of the following program segment and also mention the number of times the loop is executed.
int a,b;
for(a=6;b=4; a <= 4; a=a+ 6)
{
if(a%b==0)
break;
}
System.out.println(a);Output
6
The loop executes 0 times.
Explanation
a is initialized to 6 and as the loop condition is false before the first iteration itself so the loop doesn't execute.
Question 6
Give the output of the following program segment and also mention how many times the loop is executed.
int i;
for(i = 5; i > 10; i++)
System.out.println(i);
System.out.println(i * 4);Output
20
The loop executes 0 times.
Explanation
i is initialized to 5 and as the loop condition is false before the first iteration itself so the loop doesn't execute. The statementSystem.out.println(i * 4); is outside the loop so it gets executed once, printing 20 to the console.
Rewrite the following programs
Question 1
Using for loop:
int i=1;
int d=5;
do
{
d=d*2;
System.out.println(d);
i++;
}
while (i<=5);Answer
int d=5;
for (int i = 1; i <= 5; i++) {
d=d*2;
System.out.println(d);
}Question 2
Using while loop:
import java.util.*;
class Number
{
public static void main(String args[])
{
int n,r;
Scanner in = new Scanner(System.in);
System.out.println("Enter a number");
n=in.nextInt();
do
{
r=n%10;
n=n/10;
System.out.println(r);
}
while(n!=0);
}
}Answer
import java.util.*;
class Number
{
public static void main(String args[])
{
int n,r;
Scanner in = new Scanner(System.in);
System.out.println("Enter a number");
n=in.nextInt();
while (n != 0) {
r=n%10;
n=n/10;
System.out.println(r);
}
}
}Solutions to Unsolved Java Programs
Question 1
Write the programs in Java to display the first ten terms of the following series:
(a) 0, 1, 2, 3, 6,
public class Tribonacci
{
public void displaySeries() {
int a = 0, b = 1, c = 2;
System.out.print(a + ", " + b + ", " + c);
for (int i = 0; i < 7; i++) {
int n = a + b + c;
System.out.print(", " + n);
a = b;
b = c;
c = n;
}
}
}Output
(b) 1, -3, 5, -7, 9,
public class SeriesB
{
public void displaySeries() {
int term = 1;
System.out.print(term);
for (int i = 2; i <= 10; i++) {
term += 2;
if (i % 2 == 0)
System.out.print(", " + (-term));
else
System.out.print(", " + term);
}
}
}Output
(c) 0, 3, 8, 15,
public class Series
{
public void generateSeries() {
int term = 0;
System.out.print(term);
for (int i = 3; i < 20; i = i + 2) {
term += i;
System.out.print(", " + term);
}
}
}Output
(d) 1, 11, 111, 1111,
public class Series
{
public void generateSeries() {
int term = 1;
for (int i = 1; i <= 10; i++) {
System.out.print(term + ", ");
term = term * 10 + 1;
}
}
}Output
(e) 1, 12, 123, 1234,
public class Series
{
public void generateSeries() {
for (int i = 1; i <= 10; i++) {
for (int j = 1; j <= i; j++) {
System.out.print(j);
}
System.out.print(", ");
}
}
}Output
Question 2
Write the programs in Java to find the sum of the following series:
(a) S = 1 + 1 + 2 + 3 + 5 + ....... to n terms
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter n: ");
int n = in.nextInt();
int a = 1, b = 1;
int sum = a + b;
for (int i = 3; i <= n; i++) {
int term = a + b;
sum += term;
a = b;
b = term;
}
System.out.println("Sum=" + sum);
}
}Output
(b) S = 2 - 4 + 6 - 8 + ....... to n
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter n: ");
int n = in.nextInt();
int sum = 0;
for (int i = 1, j = 2; i <= n; i++, j = j + 2) {
if (i % 2 == 0) {
sum -= j;
}
else {
sum += j;
}
}
System.out.println("Sum=" + sum);
}
}Output
(c) S = 1 + (1+2) + (1+2+3) + ....... + (1+2+3+ ....... + n)
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter n: ");
int n = in.nextInt();
int sum = 0, term = 0;
for (int i = 1; i <= n; i++) {
term += i;
sum += term;
}
System.out.println("Sum=" + sum);
}
}Output
(d) S = 1 + (1*2) + (1*2*3) + ....... + (1*2*3* ....... * n)
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter n: ");
int n = in.nextInt();
int sum = 0, term = 1;
for (int i = 1; i <= n; i++) {
term *= i;
sum += term;
}
System.out.println("Sum=" + sum);
}
}Output
(e) S = 1 + (1 + 2) / (1 * 2) + (1 + 2 + 3) / (1 * 2 * 3) + ....... + (1 + 2 + 3 ....... + n) / (1 * 2 * 3 * ....... * n)
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter n: ");
int n = in.nextInt();
double seriesSum = 0.0;
int sum = 0;
double prod = 1.0;
for (int i = 1; i <= n; i++) {
sum += i;
prod *= i;
double term = sum / prod;
seriesSum += term;
}
System.out.println("Sum=" + seriesSum);
}
}Output
Question 3
Write the programs to find the sum of the following series:
(a) S = a + a2 + a3 + ....... + an
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter a: ");
int a = in.nextInt();
System.out.print("Enter n: ");
int n = in.nextInt();
int sum = 0;
for (int i = 1; i <= n; i++) {
sum += Math.pow(a, i);
}
System.out.println("Sum=" + sum);
}
}Output
(b) S = (a+1) + (a+2) + (a+3) + ....... + (a+n)
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter a: ");
int a = in.nextInt();
System.out.print("Enter n: ");
int n = in.nextInt();
int sum = 0;
for (int i = 1; i <= n; i++) {
sum += a + i;
}
System.out.println("Sum=" + sum);
}
}Output
(c) S = (a/2) + (a/5) + (a/8) + (a/11) + ....... + (a/20)
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter a: ");
int a = in.nextInt();
double sum = 0;
for (int i = 2; i <= 20; i = i + 3) {
sum += a / (double)i;
}
System.out.println("Sum=" + sum);
}
}Output
(d) S = (1/a) + (2/a2) + (3/a3) + ....... to n
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter a: ");
int a = in.nextInt();
System.out.print("Enter n: ");
int n = in.nextInt();
double sum = 0;
for (int i = 1; i <= n; i++) {
sum += (i / Math.pow(a, i));
}
System.out.println("Sum=" + sum);
}
}Output
(e) S = a - a3 + a5 - a7 + ....... to n
import java.util.Scanner;
public class Series
{
public void computeSeriesSum() {
Scanner in = new Scanner(System.in);
System.out.print("Enter a: ");
int a = in.nextInt();
System.out.print("Enter n: ");
int n = in.nextInt();
int sum = 0;
for (int i = 1, j = 1; i <= n; i = i + 2, j++) {
if (j % 2 == 0)
sum -= Math.pow(a, i);
else
sum += Math.pow(a, i);
}
System.out.println("Sum=" + sum);
}
}Output
Question 4
Write a program to enter two numbers and check whether they are co-prime or not.
[Two numbers are said to be co-prime, if their HCF is 1 (one).]
Sample Input: 14, 15
Sample Output: They are co-prime.
import java.util.Scanner;
public class Coprime
{
public void checkCoprime() {
Scanner in = new Scanner(System.in);
System.out.print("Enter a: ");
int a = in.nextInt();
System.out.print("Enter b: ");
int b = in.nextInt();
int hcf = 1;
for (int i = 1; i <= a && i <= b; i++) {
if (a % i == 0 && b % i == 0)
hcf = i;
}
if (hcf == 1)
System.out.println(a + " and " + b + " are co-prime");
else
System.out.println(a + " and " + b + " are not co-prime");
}
}Output
Question 5
Write a program to input a number. Display the product of the successors of even digits of the number entered by user.
Input: 2745
Output: 15
[Hint: The even digits are: 2 and 4
The product of successor of even digits is: 3*5= 15]
import java.util.Scanner;
public class EvenSuccessor
{
public void computeProduct() {
Scanner in = new Scanner(System.in);
System.out.print("Enter the number: ");
int num = in.nextInt();
int orgNum = num;
int prod = 1;
while (num != 0) {
int digit = num % 10;
num /= 10;
if (digit % 2 == 0)
prod = prod * (digit + 1);
}
if (prod == 1)
System.out.println("No even digits in " + orgNum);
else
System.out.println("Product of even digits successors is "
+ prod);
}
}Output
Question 6
Write a program to input a number and check and print whether it is a Pronic number or not. [Pronic number is the number which is the product of two consecutive integers.]
Examples:
12 = 3 * 4
20 = 4 * 5
42 = 6 * 7
import java.util.Scanner;
public class PronicNumber
{
public void pronicCheck() {
Scanner in = new Scanner(System.in);
System.out.print("Enter the number to check: ");
int num = in.nextInt();
boolean isPronic = false;
for (int i = 1; i <= num - 1; i++) {
if (i * (i + 1) == num) {
isPronic = true;
break;
}
}
if (isPronic)
System.out.println(num + " is a pronic number");
else
System.out.println(num + " is not a pronic number");
}
}Output
Question 7
A prime number is said to be 'Twisted Prime', if the new number obtained after reversing the digits is also a prime number. Write a program to accept a number and check whether the number is 'Twisted Prime' or not.
Sample Input: 167
Sample Output: 761
167 is a 'Twisted Prime'.
import java.util.Scanner;
public class TwistedPrime
{
public void twistedPrimeCheck() {
Scanner in = new Scanner(System.in);
System.out.print("Enter number: ");
int num = in.nextInt();
if (num == 1) {
System.out.println(num + " is not a twisted prime number");
}
else {
boolean isPrime = true;
for (int i = 2; i <= num / 2; i++) {
if (num % i == 0) {
isPrime = false;
break;
}
}
if (isPrime) {
int t = num;
int revNum = 0;
while (t != 0) {
int digit = t % 10;
t /= 10;
revNum = revNum * 10 + digit;
}
for (int i = 2; i <= revNum / 2; i++) {
if (revNum % i == 0) {
isPrime = false;
break;
}
}
}
if (isPrime)
System.out.println(num + " is a twisted prime number");
else
System.out.println(num + " is not a twisted prime number");
}
}
}Output
Question 8
Write a program to input a number and check whether it is a prime number or not. If it is not a prime number then display the next number that is prime.
Sample Input: 14
Sample Output: 17
import java.util.Scanner;
public class PrimeCheck
{
public void primeCheck() {
Scanner in = new Scanner(System.in);
System.out.print("Enter number: ");
int num = in.nextInt();
boolean isPrime = true;
for (int i = 2; i <= num / 2; i++) {
if (num % i == 0) {
isPrime = false;
break;
}
}
if (isPrime) {
System.out.println(num + " is a prime number");
}
else {
for (int newNum = num + 1; newNum <= Integer.MAX_VALUE; newNum++) {
isPrime = true;
for (int i = 2; i <= newNum / 2; i++) {
if (newNum % i == 0) {
isPrime = false;
break;
}
}
if (isPrime) {
System.out.println("Next prime number = " + newNum);
break;
}
}
}
}
}Output
Question 9
A number is said to be Duck if the digit zero is (0) present in it. Write a program to accept a number and check whether the number is Duck or not. The program displays the message accordingly. (The number must not begin with zero)
Sample Input: 5063
Sample Output: It is a Duck number.
Sample Input: 7453
Sample Output: It is not a Duck number.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class DuckNumber
{
public void duckNumberCheck() throws IOException {
InputStreamReader reader = new InputStreamReader(System.in);
BufferedReader in = new BufferedReader(reader);
System.out.print("Enter number: ");
boolean isDuck = false;
boolean firstZero = false;
int c = 0, d;
/*
* 10 is the ASCII code of newline
* We will read from inputstream
* one character at a time till we
* encounter a newline i.e. enter
*/
while((d = in.read()) != 10) {
char ch = (char)d;
if (c == 0 && ch == '0' )
firstZero = true;
if (!firstZero && ch == '0')
isDuck = true;
c++;
}
if (isDuck)
System.out.println("Duck Number");
else
System.out.println("Not a Duck Number");
}
}Output
Question 10
Write a program that inputs number of runs made by a cricket player on each ball. Entering runs as -1 should display the message that player is out. Finally it displays the number of runs made and balls played by the player.
import java.util.Scanner;
public class PlayerScore
{
public void computeScore() {
Scanner in = new Scanner(System.in);
int runs = 0, balls = 0, r = 0;
do {
System.out.print("Enter runs: ");
r = in.nextInt();
if (r == -1)
System.out.println("Player is out");
else
runs += r;
balls++;
}
while(r != -1);
System.out.println("Total Runs: " + runs);
System.out.println("Total Balls: " + balls);
}
}Output
Question 11
A computerised bus charges fare from each of its passengers based on the distance travelled as per the tariff given below:
| Distance (in km) | Charges |
|---|---|
| First 5 km | ₹80 |
| Next 10 km | ₹10/km |
| More than 15 km | ₹8/km |
As the passenger enters the bus, the computer prompts 'Enter distance you intend to travel'. On entering the distance, it prints his ticket and the control goes back for the next passenger. At the end of journey, the computer prints the following:
- the number of passenger travelled
- total fare received
Write a program to perform the above task.
[Hint: Perform the task based on user controlled loop]
import java.util.Scanner;
public class BusTravel
{
public void busTravel() {
Scanner in = new Scanner(System.in);
int dist, tf = 0, tp = 0;
System.out.println("Enter distance as -1 to complete the journey");
while (true) {
System.out.print("Enter distance you intend to travel: ");
dist = in.nextInt();
int f = 0;
if (dist == -1) {
break;
}
else if (dist <= 5) {
f = 80;
}
else if (dist <= 15) {
f = 80 + ((dist - 5) * 10);
}
else {
f = 80 + 100 + ((dist - 15) * 8);
}
tf += f;
tp++;
System.out.println("Your fare is " + f);
}
System.out.println("Total Passengers: " + tp);
System.out.println("Total Fare: " + tf);
}
}Output
Question 12
A special two-digit number is such that when the sum of its digits is added to the product of its digits, the result is equal to the original two-digit number.
Example: Consider the number 59.
Sum of digits = 5 + 9 = 14
Product of digits = 5 * 9 = 45
Sum of the sum of digits and product of digits = 14 + 45 = 59
Write a program to accept a two-digit number. Add the sum of its digits to the product of its digits. If the value is equal to the number input, then display the message "Special two—digit number" otherwise, display the message "Not a special two-digit number".
import java.util.Scanner;
public class SpecialNumber
{
public void checkNumber() {
Scanner in = new Scanner(System.in);
System.out.print("Enter a 2 digit number: ");
int orgNum = in.nextInt();
int num = orgNum;
int count = 0, digitSum = 0, digitProduct = 1;
while (num != 0) {
int digit = num % 10;
num /= 10;
digitSum += digit;
digitProduct *= digit;
count++;
}
if (count != 2)
System.out.println("Invalid input, please enter a 2-digit number");
else if ((digitSum + digitProduct) == orgNum)
System.out.println("Special 2-digit number");
else
System.out.println("Not a special 2-digit number");
}
}Output
Question 13
Write a program to input a number. Check and display whether it is a Niven number or not. (A number is said to be Niven which is divisible by the sum of its digits).
Example: Sample Input 126
Sum of its digits = 1 + 2 + 6 = 9 and 126 is divisible by 9.
import java.util.Scanner;
public class NivenNumber
{
public void checkNiven() {
Scanner in = new Scanner(System.in);
System.out.print("Enter number: ");
int num = in.nextInt();
int orgNum = num;
int digitSum = 0;
while (num != 0) {
int digit = num % 10;
num /= 10;
digitSum += digit;
}
/*
* digitSum != 0 check prevents
* division by zero error for the
* case when users gives the number
* 0 as input
*/
if (digitSum != 0 && orgNum % digitSum == 0)
System.out.println(orgNum + " is a Niven number");
else
System.out.println(orgNum + " is not a Niven number");
}
}Output
Question 14
Write a program to accept a number and check whether it is a 'Spy Number' or not. (A number is spy if the sum of its digits equals the product of its digits.)
Example: Sample Input: 1124
Sum of the digits = 1 + 1 + 2 + 4 = 8
Product of the digits = 1*1*2*4 = 8
import java.util.Scanner;
public class SpyNumber
{
public void spyNumCheck() {
Scanner in = new Scanner(System.in);
System.out.print("Enter Number: ");
int num = in.nextInt();
int digit, sum = 0;
int orgNum = num;
int prod = 1;
while (num > 0) {
digit = num % 10;
sum += digit;
prod *= digit;
num /= 10;
}
if (sum == prod)
System.out.println(orgNum + " is Spy Number");
else
System.out.println(orgNum + " is not Spy Number");
}
}Output
Question 15
You can multiply two numbers 'm' and 'n' by repeated addition method.
For example, 5 * 3 = 15 can be performed by adding 5 three times ⇒ 5 + 5 + 5 = 15
Similarly, successive subtraction of two numbers produces 'Quotient' and 'Remainder' when a number 'a' is divided by 'b' (a>b).
For example, 5/2 ⇒ Quotient = 2 and Remainder = 1
Follow steps shown below:
| Process | Result | Counter |
|---|---|---|
| 5 - 2 | 3 | 1 |
| 3 - 2 | 1 | 2 |
Sample Output: The last counter value represents 'Quotient' ⇒ 2
The last result value represents 'Remainder' ⇒ 1
Write a program to accept two numbers. Perform multiplication and division of the numbers as per the process shown above by using switch case statement.
import java.util.Scanner;
public class Arithmetic
{
public void computeResult() {
Scanner in = new Scanner(System.in);
System.out.print("Enter first number: ");
int a = in.nextInt();
System.out.print("Enter second number: ");
int b = in.nextInt();
System.out.println("1. Multiplication");
System.out.println("2. Division");
System.out.print("Enter your choice: ");
int ch = in.nextInt();
switch (ch) {
case 1:
int rMul = 0;
for (int i = 1; i <= b; i++) {
rMul += a;
}
System.out.println("Multiplication result = " + rMul);
break;
case 2:
int count = 0, t = a;
while (t > b) {
t -= b;
count++;
}
System.out.println("Divison Result");
System.out.println("Quotient = " + count);
System.out.println("Remainder = " + t);
break;
default:
System.out.println("Incorrect Choice");
break;
}
}
}Output
Question 16
Using a switch statement, write a menu driven program to:
(a) generate and display the first 10 terms of the Fibonacci series
0, 1, 1, 2, 3, 5
The first two Fibonacci numbers are 0 and 1, and each subsequent number is the sum of the previous two.
(b) find the sum of the digits of an integer that is input by the user.
Sample Input: 15390
Sample Output: Sum of the digits = 18
For an incorrect choice, an appropriate error message should be displayed.
import java.util.Scanner;
public class FibonacciNDigitSum
{
public static void main(String args[]) {
Scanner in = new Scanner(System.in);
System.out.println("1. Fibonacci Series");
System.out.println("2. Sum of digits");
System.out.print("Enter your choice: ");
int ch = in.nextInt();
switch (ch) {
case 1:
int a = 0, b = 1;
System.out.print(a + " " + b);
/*
* i is starting from 3 below
* instead of 1 because we have
* already printed 2 terms of
* the series. The for loop will
* print the series from third
* term onwards.
*/
for (int i = 3; i <= 10; i++) {
int term = a + b;
System.out.print(" " + term);
a = b;
b = term;
}
break;
case 2:
System.out.print("Enter number: ");
int num = in.nextInt();
int sum = 0;
while (num != 0) {
sum += num % 10;
num /= 10;
}
System.out.println("Sum of Digits " + " = " + sum);
break;
default:
System.out.println("Incorrect choice");
break;
}
}
}Output
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